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Use the worked example above to help you solve this problem. A ball is thrown upward from the top of a building at an angle of $30.0_{?}$ to the horizontal and with an initial speed of $16.0m/s$. The point of release is $h=46.0m$ above the ground. (a) How long does it take for the ball to hit the ground? w Your response differs from the correct answer by more than $10%$. Double check your calculations. S (b) Find the ball's speed at impact. $m/s$ (c) Find the horizontal range of the ball. $m$ EXERCISE HINTS: GETTING STARTED I I'M STUCK! Suppose the ball is thrown from the same height as in the PRACTICE IT problem at an angle of $34.0_{?}$ below the horizontal. If it strikes the ground $44.4m$ away, find the following. (Hint: For part (a), use the equation for the $x$-displacement to eliminate $v_{0}t$ from the equation for the $y$-displacement.) (a) the time of flight S (b) the initial speed $m/s$ (c) the speed and angle of the velocity vector with respect to the horizontal at impact speed $m/s$ angle - below the horizontal

1) initial speed (u) = 16 m/s h = 46 m theta = 30 degree A) using the equation of motion in vertical direction :