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The World Almanact features a "perpetual calendar," a collection of 14 possible calendars. Does this suffice to be sure there is a calendar for every conceivable year? Yes No Why? There are 12 choices for the months, and 2 choices for the year (leap or non-leap). The total number of calendars is $12+2$ $=14$. There are 365 choices for the day in a regular year and 366 choices for the day in a leap year. The total number of calendars is 731 . There are 7 choices for the day of January $1_{st}$ and 2 choices for the year (leap or non-leap). The total number of calendars is $7+2=9$. There are 7 choices for the day of January $1_{st}$ and 2 choices for the year (leap or non-leap). The total number of calendars is $7?2=14$. There are 12 choices for the months, and 2 choices for the year (leap or non-leap). The total number of calendars is 12 . 2 $=24$.

We know there are seven days a week. The year can begin on any of the seven days of the week. Each year can be either a leap here or a non leap year,

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