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(Solved): Suppose that \( \sum_{i=1}^{112} a_{i}=26 \) and \( \sum_{i=1}^{112} b_{i}=21 \). Compute the sum. ...
Suppose that \( \sum_{i=1}^{112} a_{i}=26 \) and \( \sum_{i=1}^{112} b_{i}=21 \). Compute the sum. \[ \sum_{i=1}^{112}\left(-7 a_{i}+4 b_{i}\right) \]
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Given ?i=1112ai=
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