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(Solved): Suppose S is a set that contains n as an element of Q and n is equal to 2^3k 3^m where k and m are e ...



Suppose S is a set that contains n as an element of Q and n is equal to 2^3k 3^m where k and m are element of Z. Show that S is a subgroup of Q without zero under ordinary multiplication.

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Let Q×be the set of all non zero rational numbers i.e. the rational number Q without zero.We are given that, S= the set contains n as an element of Q.
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