Home / Expert Answers / Chemistry / review-for-the-second-chem-301-exam-the-exam-is-largely-based-on-stoichiometry-there-are-3-rules-pa213

(Solved): Review for the second chem 301 exam The exam is largely based on stoichiometry. There are 3 rules ...



Review for the second chem 301 exam
The exam is largely based on stoichiometry. There are 3 rules of stoichiometry that alway

Review for the second chem 301 exam The exam is largely based on stoichiometry. There are 3 rules of stoichiometry that always apply: - BALANCE the reaction - Convert TO MOLES - Use the RATIO of reaction coefficients to compare moles of different species - (if needed) convert MOLES TO unit requested Stoichiometry - basic 1. \( \mathrm{O}_{2} \) may be produced from \( \mathrm{KClO}_{3} \) by the reaction (unbalanced): \( \mathrm{KClO} \mathrm{O}_{3} \rightarrow \mathrm{KCl}+\mathrm{O}_{2} \) A. Balance the equation: \[ 2 \mathrm{KClO}_{3} \rightarrow 2 \mathrm{KCl}+3 \mathrm{O}_{2} \] B. If you start with 2 moles of \( \mathrm{KClO}_{3} \) how many moles of \( \mathrm{KCl} \) will be produced? 2 moles of \( k(1 \) 2. Given the reaction: \( 4 \mathrm{NH}_{3}+5 \mathrm{O}_{2} \rightarrow 4 \mathrm{NQ}+6 \mathrm{H}_{2} \mathrm{O}_{\text {i }} \). A. If I start out with \( 100.0 \mathrm{~g} \mathrm{NH} 3 \) and excess \( \mathrm{O}_{2} \), how many grams of \( \mathrm{NO} \) is it possible to produce? \( \mathrm{NH}_{3}=(14.007)+3(1.008)=17.031 \mathrm{glmol} 100 \mathrm{gNH} 3\left(\frac{1 \text { mole NHt }}{17.031}\right. \) \( O_{2}=2(15.999)=31.998 \mathrm{~g} / \mathrm{mol} \) \( N_{0}=14.007+15.999=30.006 \mathrm{~g} / \mathrm{mol} \) \( =5.872 \mathrm{~mol} \) B. If I start out with \( 100.0 \mathrm{~g} \mathrm{NH}_{3} \) and \( 170.0 \mathrm{~g} \mathrm{O} \mathrm{O}_{2} \). how many grams of NO is it possible to produce?


We have an Answer from Expert

View Expert Answer

Expert Answer


We have an Answer from Expert

Buy This Answer $5

Place Order

We Provide Services Across The Globe