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A car moves in a straight line such that for a short time its velocity is defined by \( \mathrm{v}-\left(3 \mathrm{t}^{2}+2 \mathrm{t}\right) \mathrm{fts} \), where \( \mathrm{t} \) is in seconds. Determine its position and acceleration when \( t-3 \) seconds and \( t_{0}=0: s_{0}=0 \). \( 36 \mathrm{ft}, 20 \mathrm{ft} / \mathrm{s}^{2} \) \( 24 \mathrm{ft}, 38 \mathrm{ft} / \mathrm{s}^{2} \) \( 30 \mathrm{ft}, 28 \mathrm{ft} / \mathrm{s}^{2} \) \( 20 \mathrm{ft} \cdot 36 \mathrm{ft} / \mathrm{s}^{2} \)

Solution:given Acceleration of

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