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(Solved): r=(e5tcos(6t),e5tsin(6t),e5t) gth function s(t) : (with initial noint t=m ...




\[
\mathbf{r}=\left(e^{5 t} \cos (6 t), e^{5 t} \sin (6 t), e^{5 t}\right)
\]
gth function \( s(t) \) : (with initial noint \
gth function : (with initial noint


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The given function is r(t)=since the arclength function s(t)=?0t(x?(u))2+(y?(u))2+(z?(u))2du
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