(Solved): Please hep I will like if it is correct Hint: The moment of inertia of a uniform rod about its cente ...

Hint: The moment of inertia of a uniform rod about its center-of-mass is $$\frac{1}{12}M{L}^2$$. The acceleration of gravity is $$9.8\mathrm{m}/{\mathrm{s}}^2$$. Consider a uniform rod with a mass $$M=$$ $$8\mathrm{kg}$$ and length $$L=2.9\mathrm{m}$$ pivoted on a frictionless horizontal bearing at a point $$O$$ $$(\frac{2}{3}L$$ from the lower end $$)$$, as shown in the figure. The period of this pendulum in the small angle approximation is given by Answer in units of $$\mathrm{s}$$,