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(Solved): please do not answer if you are not sure about your answer thanks \( (x-1) y^{\prime}+3 y=\frac{ ...


\( (x-1) y^{\prime}+3 y=\frac{1+(x-1) \sec ^{2} x}{(x-1)^{3}}, \quad y(0)=-1 \)

please do not answer if you are not sure about your answer

thanks

\( (x-1) y^{\prime}+3 y=\frac{1+(x-1) \sec ^{2} x}{(x-1)^{3}}, \quad y(0)=-1 \)


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Rewrite the differential equation as follows: y?+3x?1y=1+(x?1)sec2
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