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parts a-d pleaseee

Use the sample data and confidence level given below to complete parts (a) through (d). A drug is used to help prevent blood clots in certain patients. In clinical trials, among 4575 patients treated with the drug 164 developed the adverse reaction of nausea. Construct a $90%$ confidence interval for the proportion of adverse reactions. a) Find the best point estimate of the population proportion $p$. (Round to three decimal places as needed.) b) Identify the value of the margin of error $E$. $E=$ (Round to three decimal places as needed.) c) Construct this confidence interval. $<p<$ (Round to three decimal places as needed.) d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below. A. $90%$ of sample proportions will fall between the lower bound and the upper bound. B. One has $90%$ confidence that the sample proportion is equal to the population proportion. C. There is a $90%$ chance that the true value of the population proportion will fall between the lower bound and the upper bound.

Solution:a) The best point estimate of the population proportion p is the sample proportion:p?=1644,575?0.0359b) The margin

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