(Solved): need answer to part 5  Pain: A recent survey asked 806 people how many days they would wait to ...

Pain: A recent survey asked 806 people how many days they would wait to seek medical treatment if they were suffering pain that interfered with their ability to work. The results are presented in the following table, Consider these 806 people to be a population. Let \( X \) be the number of days for a perion fampled at randem from this populaben. (a) Construct the probability distribution of \( X \). Round the answers to three decimal piaces. Part 2 of 5 (b) Find the probability that a persen would wait for 2 days. The probabilify that a person would walt for 2 days is Part 3 of 5 (c) Find the probability that a person would wait mare than 3 days. The probability that a person would wait more than 3 days is The probability that a person would wait more than 3 days is Part 4 of 5 (d) Compute the mean \( \mu_{X} \). Round the answer to two decimal places. \[ \mu_{X}= \] Part: \( 4 / 5 \) Part 5 of 5 (e) Compute the standard deviation \( \sigma_{x} \). Round the answer to three decimal places.