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(Solved): If \( 25.0 \mathrm{~mL} \) of \( 0.17 \mathrm{M} \mathrm{NH}_{3}\left(\mathrm{~K}_{\mathrm{b}}=1.8 ...




If \( 25.0 \mathrm{~mL} \) of \( 0.17 \mathrm{M} \mathrm{NH}_{3}\left(\mathrm{~K}_{\mathrm{b}}=1.8 \times 10^{-5}\right) \) i
If \( 25.0 \mathrm{~mL} \) of \( 0.17 \mathrm{M} \mathrm{NH}_{3}\left(\mathrm{~K}_{\mathrm{b}}=1.8 \times 10^{-5}\right) \) is used to titrate \( 0.034 \mathrm{~L} \) of \( 0.78 \mathrm{M} \mathrm{HCl} \), the \( \mathrm{pH} \) is: Your Answer: Answer


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