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i dont a book alike answer...its fully of equations that the author assumes a student knows and other things that i don't fully get it, So Please take your time and explain your step by step answer, dont just do a step by step answer and dont assume me to know any step you preform along the way...make it obvious more than obvious if you know what i mean...please if you can't do this then dont answer the question because I'm gonna have to upload it again if i dont understand your answer....Thank you for understanding.

The switch in figure has been in position a for a long time. At it \( t=0 \), it moves to position \( b \). Find \( v(0) \). Find \( \tau \). a) \( 5 \mathrm{~V} \mathrm{~b} 10 \mathrm{~V} \) c) \( 15 \mathrm{~V} \) d) \( 20 \mathrm{~V} \mathrm{e}) 25 \mathrm{~V} \) Find \( v(\infty) \). a) \( 2 \mathrm{~s} \) b) \( 4 \mathrm{sc} \) c) \( 6 \mathrm{~s} \) d) \( 8 \mathrm{se} \) e) \( 10 \mathrm{~s} \) Find \( v(t) \) for \( t>0 \). a) \( 4 \mathrm{~V} \) b) \( 8 \mathrm{~V} \mathrm{c} \) c) \( 12 \mathrm{~V} \mathrm{~d} \) ) \( 16 \mathrm{~V} \mathrm{e} \) ) \( 20 \mathrm{~V} \) a) \( \left.\left.\left.\left.\left(8+12 \mathrm{e}^{-t / 4}\right) \mathrm{V} \mathrm{b}\right)\left(4+3 \mathrm{e}^{-t 4}\right) \mathrm{V} \mathrm{c}\right)\left(2+12 \mathrm{e}^{-t 4}\right) \mathrm{V} \mathrm{d}\right)\left(8+10 \mathrm{e}^{-t 4}\right) \mathrm{V} \mathrm{e}\right)\left(6+12 \mathrm{e}^{-t 2}\right) \mathrm{V} \)

at t=0- the switch is position a then the circuit diagram 60v 24V 6? 3? 2F V(0?) the