(Solved): H2(g)+I2(g)2HI(g) At 600K, the rate constant (k) for this reaction is 2.7104M ...

$${\mathrm{H}}_2(\mathrm{g})+{\mathrm{I}}_2(\mathrm{g})?2\mathrm{HI}(\mathrm{g})$$ At $$600\mathrm{K}$$, the rate constant $$(\mathrm{k})$$ for this reaction is $$2.7\times 10^{?4}{\mathrm{M}}^{?1}{\mathrm{s}}^{?1}$$. When the temperature is increased to $$650\mathrm{K}$$, the rate constant increases to $$3.5\times 10^{?3}{\mathrm{M}}^{?1}{\mathrm{s}}^{?1}$$. a. Calculate the activation energy $$\left(E_a\right)$$ for this reaction. b. What will the rate constant be for this reaction at $$700\mathrm{K}$$ ?