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DUE IN 2 DAYS! Please help! Assume that a procedure yields a binomial distribution with n = 983 trials and the probability of success for one trial is p=64\% Find the mean for this binomial distribution. (Round answer to one decimal place.) mu = Find the standard deviation for this distribution . (Round answer to two decimal places .) sigma = Use the range rule of thumb to find the minimum usual value and the maximum usual value mu + 2sigma Enter answer as an interval using square-brackets only with whole numbers. U * 5ualvalues =

Solution:Given data : p = 64% = 0.64Sample size = n = 983Explanation:Use Binomial Distribution (mean and Standar