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(Solved): D=8mm P=33.33KN If incorrect please explain why and solve if correct just answer with "correct" f ...



\( P=\frac{100 \mathrm{kn}}{3}=33.33 \mathrm{kN} \)
\( \Sigma F_{x}=33.33 \mathrm{kN}-2 \mathrm{~V}=0 \)
\( V=16.67 \mathrm{k

D=8mm P=33.33KN

If incorrect please explain why and solve if correct just answer with "correct" for thumbs up thank you.



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33.33VVsum of horizontal force
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