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Compute the inverse Laplace transform of \[ F(s)=\frac{s+6}{s^{2}+8 s+16} e^{-5 s} \] \[ f(t)= \] (Notation: write u(t-c) for the Heaviside step function \( u_{c}(t) \) with step at \( t=c \).) If you don't get this in 2 tries, you can get a hint.

F(s)=s+6s2+8s+16e?3s apply inverse transform rule L?1{F(s)}=f(t) then L?1{e?asF(s)}=u(t?a)f(t?a) u(t-c) for heavy side step function for s+6(s+4)2e?3s