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As shown in the figure, a wooden ball with mass \( m_{2} \) is initially at rest on a horizontal, frictionless table. A second wooden ball with mass \( m_{1} \) moving with a speed \( 2.00 \mathrm{~m} / \mathrm{s} \), collides with \( m_{2} \). Assume \( m_{1} \) moves initially along the \( +x \)-axis. After the collision, \( m_{1} \) moves with speed \( 1.00 \mathrm{~m} / \mathrm{s} \) at an angle of \( \theta=48.00^{\circ} \) to the positive \( x \)-axis. (Assume \( m_{1}=0.200 \mathrm{~kg} \) and \( \mathrm{m}_{2}=0.300 \mathrm{~kg} \).) (a) Determine the speed (in \( \mathrm{m} / \mathrm{s} \) ) of the \( 0.300 \mathrm{~kg} \) ball after the collision. \[ \mathrm{m} / \mathrm{s} \] (b) Find the fraction of kinetic energy transferred away or transformed to other forms of energy in the collision. \[ \frac{|\Delta K|}{K_{i}}= \]

a) Along x axis applying momentum conservation, we get, (m