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(Solved): An unmarked police car traveling a constant 95.0km/h is passed by a speeder traveling 130km/h. ...




An unmarked police car traveling a constant \( 95.0 \mathrm{~km} / \mathrm{h} \) is passed by a speeder traveling \( 130 \mat
Precisely \( 2.00 \) s after the speeder passes, the police officer steps on the accelerator, if the police cars accolerabon
An unmarked police car traveling a constant is passed by a speeder traveling . Precisely s after the speeder passes, the police officer steps on the accelerator, if the police car's accolerabon is 2 in , how much time passes before the police car overtakes fie speeder after the speeder passes (assumed moving at constant speed)?


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The velocity of police car Vp= 95 km/h =47518m/sThe velocity of speeder Vs= 130 km/h
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