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(Solved): A restaurant wants to test a new in-store marketing scheme in a small number of stores before rollin ...



A restaurant wants to test a new in-store marketing scheme in a small number of stores before rolling it out nationwide. The new ad promotes a premium drink that they want to increase the sales of. 5 locations are chosen at random and the number of drinks sold are recorded for 2 months before the new ad campaign and 2 months after. The average difference in the sales quantity (after - before) is -114.856 with a standard deviation of 54.194. Calculate a 95% confidence interval to estimate the true average difference in nationwide sales quantity before the ad campaign and after.

 

1) (-117.6324, -112.0796)

2) (-177.1574, -52.5546)

3) (-182.1467, -47.5653)

4) (182.1467, -47.5653)

5) (-139.0923, -90.6197)



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sample mean = X_bar = -114.856 point of estimate sample std . Deviation = s 54.194 S
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