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(Solved): A \( 5.7650 \) gram sample of beef was analyzed for its \( \mathrm{N}(14 \mathrm{~g} / \mathrm{mol ...



A \( 5.7650 \) gram sample of beef was analyzed for its \( \mathrm{N}(14 \mathrm{~g} / \mathrm{mole}) \) content and the libe

A \( 5.7650 \) gram sample of beef was analyzed for its \( \mathrm{N}(14 \mathrm{~g} / \mathrm{mole}) \) content and the liberated \( \mathrm{NH}_{3} \) was collected in a \( 52.80 \mathrm{~mL} \) of \( 0.1793 \mathrm{M} \mathrm{HCl} \) and \( 4.39 \mathrm{~mL} \) back titration with \( 0.0118 \mathrm{M} \mathrm{NaOH} \) was required. Calculate the percentage protein in the beef sample. (Answers should be written in 2 decimals place and do not include the UNIT)


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To solve this problem, we need to first determine the mass of nitrogen present in the beef sample. To do this, we can use the volume and concent
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