Home /
Expert Answers /
Physics /
a-2-1-carat-diamond-is-grown-under-a-high-pressure-of-58-times-10-9-mathrm-n-mathrm-m-pa455

A 2.1-carat diamond is grown under a high pressure of \( 58 \times 10^{9} \mathrm{~N} / \mathrm{m}^{2} \). One carat equals \( 0.200 \mathrm{~g} \). Use \( 3.52 \mathrm{~g} / \mathrm{cm}^{3} \) for the density of diamond and \( 4.43 \times 10^{11} \mathrm{~N} / \mathrm{m}^{2} \) for the bulk modulus of diamond. What is the change in volume \( \Delta V \), in cubic centimeters, of a spherical 2.1-carat diamond when it expands after being removed from the chamber and exposed to \( \Delta V= \) \( \mathrm{cm}^{3} \) atmospheric pressure? What is the increase in the diamond's radius, \( \Delta r ? \) \( \Delta r= \) \( \mathrm{cm} \)

2.1 carat diamond grown, under high pressure p1=58×109N/m2 atmo