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(Solved): 66% of all Americans live in cities with population greater than 100,000 people. If 33 Americans a ...



\( 66 \% \) of all Americans live in cities with population greater than 100,000 people. If 33 Americans are randomly selecte

of all Americans live in cities with population greater than 100,000 people. If 33 Americans are randomly selected, find the probability that a. Exactly 22 of them live in cities with population greater than 100,000 people. b. At most 23 of them live in cities with population greater than 100,000 people. c. At least 21 of them live in cities with population greater than 100,000 people. d. Between 19 and 25 (including 19 and 25) of them live in cities with population greater than 100,000 people.


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Given: p=0.66 n=33Solution: It's a binomial distribution problem.By using the excel
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