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(Solved): 11) \( [1301-2-11-1] \) You apply a force of \( F=257 \mathrm{~N} \) to a box at an angle of \( \th ...




11) \( [1301-2-11-1] \) You apply a force of \( F=257 \mathrm{~N} \) to a box at an angle of \( \theta=29.8^{\circ} \) below
11) \( [1301-2-11-1] \) You apply a force of \( F=257 \mathrm{~N} \) to a box at an angle of \( \theta=29.8^{\circ} \) below the horizontal. The box moves a distance of \( \mathrm{d}=4.20 \mathrm{~m} \) to the right across a surface where the coefficient of kinetic friction is \( \mu_{\mathrm{k}}=0.214 \). If the box has a mass of \( \mathrm{m}=8.75 \mathrm{~kg} \), what is the work done by friction? \( \mathrm{g}=9.80 \mathrm{~m} / \mathrm{s}^{2} \) a) \( -937 \mathrm{~J} \) b) \( -192 \mathrm{~J} \) c) \( 192 \mathrm{~J} \) d) \( 77.1 \mathrm{~J} \) e) \( -77.1 \mathrm{~J} \)


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We first need to determine the value of friction force, f which in turn can be determined by the equation f=?N, where ? is the coefficient of friction
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